3.139 \(\int \cot ^4(e+f x) (a+a \sin (e+f x))^m \, dx\)

Optimal. Leaf size=89 \[ \frac {4 \sqrt {2} \sqrt {1-\sin (e+f x)} \sec (e+f x) (a \sin (e+f x)+a)^{m+3} F_1\left (m+\frac {5}{2};-\frac {3}{2},4;m+\frac {7}{2};\frac {1}{2} (\sin (e+f x)+1),\sin (e+f x)+1\right )}{a^3 f (2 m+5)} \]

[Out]

4*AppellF1(5/2+m,4,-3/2,7/2+m,1+sin(f*x+e),1/2+1/2*sin(f*x+e))*sec(f*x+e)*(a+a*sin(f*x+e))^(3+m)*2^(1/2)*(1-si
n(f*x+e))^(1/2)/a^3/f/(5+2*m)

________________________________________________________________________________________

Rubi [A]  time = 0.10, antiderivative size = 89, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {2719, 137, 136} \[ \frac {4 \sqrt {2} \sqrt {1-\sin (e+f x)} \sec (e+f x) (a \sin (e+f x)+a)^{m+3} F_1\left (m+\frac {5}{2};-\frac {3}{2},4;m+\frac {7}{2};\frac {1}{2} (\sin (e+f x)+1),\sin (e+f x)+1\right )}{a^3 f (2 m+5)} \]

Antiderivative was successfully verified.

[In]

Int[Cot[e + f*x]^4*(a + a*Sin[e + f*x])^m,x]

[Out]

(4*Sqrt[2]*AppellF1[5/2 + m, -3/2, 4, 7/2 + m, (1 + Sin[e + f*x])/2, 1 + Sin[e + f*x]]*Sec[e + f*x]*Sqrt[1 - S
in[e + f*x]]*(a + a*Sin[e + f*x])^(3 + m))/(a^3*f*(5 + 2*m))

Rule 136

Int[((a_) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_), x_Symbol] :> Simp[((b*e - a*
f)^p*(a + b*x)^(m + 1)*AppellF1[m + 1, -n, -p, m + 2, -((d*(a + b*x))/(b*c - a*d)), -((f*(a + b*x))/(b*e - a*f
))])/(b^(p + 1)*(m + 1)*(b/(b*c - a*d))^n), x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] &&  !IntegerQ[m] &&  !Int
egerQ[n] && IntegerQ[p] && GtQ[b/(b*c - a*d), 0] &&  !(GtQ[d/(d*a - c*b), 0] && SimplerQ[c + d*x, a + b*x])

Rule 137

Int[((a_) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_), x_Symbol] :> Dist[(c + d*x)^
FracPart[n]/((b/(b*c - a*d))^IntPart[n]*((b*(c + d*x))/(b*c - a*d))^FracPart[n]), Int[(a + b*x)^m*((b*c)/(b*c
- a*d) + (b*d*x)/(b*c - a*d))^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] &&  !IntegerQ[m] &&
!IntegerQ[n] && IntegerQ[p] &&  !GtQ[b/(b*c - a*d), 0] &&  !SimplerQ[c + d*x, a + b*x]

Rule 2719

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*tan[(e_.) + (f_.)*(x_)]^(p_), x_Symbol] :> Dist[(Sqrt[a + b*Si
n[e + f*x]]*Sqrt[a - b*Sin[e + f*x]])/(b*f*Cos[e + f*x]), Subst[Int[(x^p*(a + x)^(m - (p + 1)/2))/(a - x)^((p
+ 1)/2), x], x, b*Sin[e + f*x]], x] /; FreeQ[{a, b, e, f, m}, x] && EqQ[a^2 - b^2, 0] &&  !IntegerQ[m] && Inte
gerQ[p/2]

Rubi steps

\begin {align*} \int \cot ^4(e+f x) (a+a \sin (e+f x))^m \, dx &=\frac {\left (\sec (e+f x) \sqrt {a-a \sin (e+f x)} \sqrt {a+a \sin (e+f x)}\right ) \operatorname {Subst}\left (\int \frac {(a-x)^{3/2} (a+x)^{\frac {3}{2}+m}}{x^4} \, dx,x,a \sin (e+f x)\right )}{a f}\\ &=\frac {\left (2 \sqrt {2} \sec (e+f x) (a-a \sin (e+f x)) \sqrt {a+a \sin (e+f x)}\right ) \operatorname {Subst}\left (\int \frac {(a+x)^{\frac {3}{2}+m} \left (\frac {1}{2}-\frac {x}{2 a}\right )^{3/2}}{x^4} \, dx,x,a \sin (e+f x)\right )}{f \sqrt {\frac {a-a \sin (e+f x)}{a}}}\\ &=\frac {4 \sqrt {2} F_1\left (\frac {5}{2}+m;-\frac {3}{2},4;\frac {7}{2}+m;\frac {1}{2} (1+\sin (e+f x)),1+\sin (e+f x)\right ) \sec (e+f x) \sqrt {1-\sin (e+f x)} (a+a \sin (e+f x))^{3+m}}{a^3 f (5+2 m)}\\ \end {align*}

________________________________________________________________________________________

Mathematica [F]  time = 0.78, size = 0, normalized size = 0.00 \[ \int \cot ^4(e+f x) (a+a \sin (e+f x))^m \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[Cot[e + f*x]^4*(a + a*Sin[e + f*x])^m,x]

[Out]

Integrate[Cot[e + f*x]^4*(a + a*Sin[e + f*x])^m, x]

________________________________________________________________________________________

fricas [F]  time = 0.50, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (a \sin \left (f x + e\right ) + a\right )}^{m} \cot \left (f x + e\right )^{4}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(f*x+e)^4*(a+a*sin(f*x+e))^m,x, algorithm="fricas")

[Out]

integral((a*sin(f*x + e) + a)^m*cot(f*x + e)^4, x)

________________________________________________________________________________________

giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (a \sin \left (f x + e\right ) + a\right )}^{m} \cot \left (f x + e\right )^{4}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(f*x+e)^4*(a+a*sin(f*x+e))^m,x, algorithm="giac")

[Out]

integrate((a*sin(f*x + e) + a)^m*cot(f*x + e)^4, x)

________________________________________________________________________________________

maple [F]  time = 0.44, size = 0, normalized size = 0.00 \[ \int \left (\cot ^{4}\left (f x +e \right )\right ) \left (a +a \sin \left (f x +e \right )\right )^{m}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cot(f*x+e)^4*(a+a*sin(f*x+e))^m,x)

[Out]

int(cot(f*x+e)^4*(a+a*sin(f*x+e))^m,x)

________________________________________________________________________________________

maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (a \sin \left (f x + e\right ) + a\right )}^{m} \cot \left (f x + e\right )^{4}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(f*x+e)^4*(a+a*sin(f*x+e))^m,x, algorithm="maxima")

[Out]

integrate((a*sin(f*x + e) + a)^m*cot(f*x + e)^4, x)

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int {\mathrm {cot}\left (e+f\,x\right )}^4\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cot(e + f*x)^4*(a + a*sin(e + f*x))^m,x)

[Out]

int(cot(e + f*x)^4*(a + a*sin(e + f*x))^m, x)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a \left (\sin {\left (e + f x \right )} + 1\right )\right )^{m} \cot ^{4}{\left (e + f x \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(f*x+e)**4*(a+a*sin(f*x+e))**m,x)

[Out]

Integral((a*(sin(e + f*x) + 1))**m*cot(e + f*x)**4, x)

________________________________________________________________________________________